Janakalyan Sahakari Bank job recruitmemt notification

.

RRB Recruitment 2015 – Apply Online for 651 Jr, Accounts Clerk cum Typist & Other Posts: Government of India, Ministry of Railways, Railway Recruitment Board (RRB) has issued notification for the special recruitment of 651 Jr, Accounts Clerk cum Typist, Trains Clerk, Commercial Clerk & Ticket Examiner vacancies for PWD candidates. Eligible candidates can apply online from 22-08-2015 to 21-09-2015 up to 23.59 Hrs. Other details like age limit, qualification, selection process, application fee, how to apply are given below…

RRB Vacancy Details:
Total No.of Posts: 651
Name of the Posts:
1. Jr. Clerk cum Typist: 301 Posts
A. Ahmedabad: 28 Posts
B. Ajmer: 08 Posts
C. Allahabad: 20 Posts
D. Bangalore: 31 Posts
E. Bhopal: 10 Posts
F. Bhubaneswar: 04 Posts
G. Bilaspur: 24 Posts
H. Chandigarh: 08 Posts
I. Chennai: 11 Posts
J. Gorakhpur: 01 Post
K. Guwahati: 10 Posts
L. Kolkata: 62 Posts
M. Mumbai: 62 Posts
N. Muzaffarpur: 01 Post
O. Patna: 09 Posts
P. Ranchi: 11 Posts
Q. Secunderabad: 01 Post
2. Accounts Clerk cum Typist: 55 Posts
A. Ahmedabad: 03 Posts
B. Allahabad: 01 Post
C. Bangalore: 14 Posts
D. Bhopal: 01 Post
E. Chennai: 01 Post
F. Guwahati: 01 Post
G. Mumbai: 33 Posts
H. Muzaffarpur: 01 Post
3. Trains Clerk: 29 Posts
A. Ahmedabad: 06 Posts
B. Allahabad: 02 Posts
C. Bhopal: 07 Posts
D. Kolkata: 04 Posts
E. Malda: 01 Post
F. Mumbai: 07 Posts
G. Muzaffarpur: 02 Posts
4. Commercial Clerk: 86 Posts
A. Ahmedabad: 17 Posts
B. Ajmer: 07 Posts
C. Allahabad: 05 Posts
D. Bhopal: 11 Posts
E. Bhubaneswar: 01 Post
F. Bilaspur: 04 Posts
G. Chennai: 04 Posts
H. Guwahati: 01 Post
I. Kolkata: 23 Posts
J. Mumbai: 09 Posts
K. Siliguri: 02 Posts
L. Thiruvanantapuram: 02 Posts
5. Ticket Examiner: 180 Posts
A. Ahmedabad: 40 Posts
B. Ajmer: 15 Posts
C. Allahabad: 16 Posts
D. Bangalore: 23 Posts
E. Bhopal: 16 Posts
F. Bhubaneswar: 02 Posts
G. Chandigarh: 05 Posts
H. Chennai: 10 Posts
I. Guwahati: 04 Posts
J. Jammu & Srinagar: 01 Post
K. Kolkata: 19 Posts
L. Mumbai: 14 Posts
M. Ranchi: 01 Post
N. Secunderabad: 03 Posts
O. Siliguri: 04 Posts
P. Thiruvanantapuram: 07 Posts

Age Limit: Candidates age should be 18-29 years as on 01-01-2016. Age relaxations are applicable as per rules.

Educational Qualification: Candidates should possess 12th (+2 stage or its equivalent examination from recognized Board/ University/ Institute and typing speed of 30 wpm in English or 25 wpm in Hindi.

Selection Process: Selection will be made on the basis of written/ online examination, skill test, document verification & medical fitness.

Examination Fee: Candidates should have to pay Rs.100/- (for Editing/ Modification of Application fee) through online by using internet banking or debit/credit cards in any other banks except SBI or through Challan in any branch of SBI or computerized Post Office Pay-In-Slip.

How to Apply: Eligible candidates can apply online through the concerned RRB website (www.rrbahmedabad.gov.in) from 22-08-2015 to 21-09-2015 up to 23.59 Hrs.

Click for more details regarding this Job Notification

Instructions to Apply Online:
1. Log on through the website of RRB (www.rrbahmedabad.gov.in) to which the candidate wants to apply.
2. Click on the “Online Application” link.
3. Click on the “New Registration” link.
4. Fill the basic details carefully & select the post applied for.
5. Fill the other details carefully and submit the application form.
6. Registration Number & Password will be displayed on the screen.
7. Login using the Registration Number and Password.
8. Fill other relevant personal details.
9. Now pay the fee through Net Banking/ debit/ credit card/ challan form/ Pay-in-slip in any bank rather than SBI.
10. Download the blank “Template” by clicking on the link “Download Template”.
11. Affix your colour photograph (of size 3.5 cm x 3.5 cm), clear left hand thumb impression,
Signature and also copy the declaration
12. Scan the duly filled “Template” in prescribed format.
13. Submit the application form and take the printout copies of application form for future use.
14. Even after final submission if a candidate wishes to make any modifications.
15. Candidates have to pay Rs.100/- for modification for all category candidates.

Important Dates:
Starting Date to Apply Online: 22-08-2015.
Last Date to Apply Online: 21-09-2015 up to 23.59 Hrs.
Last Date for Reprint Application: 05-10-2015 .
Date of Online Fee Payment: 22-08-2015 to 20-09-2015.
Date of Offline Fee Payment (through SBI/ Post Office Challan): 22-08-2015 to 18-09-2015.
Date of Written/ Online Examination: Between 24-10-2015 to 04-11-2015.

For more details like pay scale, qualification & other information click on the link given below…

RRB – Jr, Accounts Clerk cum Typist, Clerk & Ticket Examiner Recruitment 2015	More Information
RRB – Jr, Accounts Clerk cum Typist, Clerk & Ticket Examiner Recruitment Advt	Get Details
Online Application	Click here
RRB – How to Apply	Get Details
RRB – Guidelines	Get Details
RRB – FAQ	Get Details

Other posts you might be interested in:

1. Collector Office Amravati Recruitment 2015 – Apply Online for Clerk Typist & Talathi Posts
2. Collector Office Satara Recruitment 2015 – Apply Online for 62 Clerk Typist & Talathi Posts
3. Ratnagiri Collector Office Recruitment 2015 – Apply Online for 43 Clerk Typist & Talathi Posts
4. Collector Office Dhule Recruitment 2015 – Apply Online for Clerk Typist Posts
5. Collector Office Wardha Recruitment 2015 – Apply Online for Clerk Typist

Questions on Area - Quantitative Aptitude

[Q] Find the percentage of error in the calculated area of the square if an error 2% in excess is made while measuring the side of  it. 
(a) 3.04%
(b) 2.04%
(c) 4.04%
(d) 5.04%

Solution

Answer   (c)
Explanation
---- 

Error = 2%
Let the correct value of the side of the square = 100

Then, the measured value = 100×(100+2)100=102 (∵ error 2% in excess)

Correct area of the square = 100 × 100 = 10000

Calculated area of the square = 102 × 102 = 10404

Error = 10404 - 10000 = 404

Percentage Error = ErrorActual Value×100=40410000×100=4.04%

[Q] A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. The area of the lawn is 2109 sq. m. Find the width of the road?
(a) 4
(b) 5
(c) 3
(d) 6

Solution

Answer   (c)
Explanation
---- 
Area of the park = (60 x 40) m² = 2400 m².
Area of the lawn = 2109 m².
Area of the crossroads = (2400 - 2109) m² = 291 m².
Let the width of the road be x metres. Then,
60x + 40x - x² = 291
x² - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.

[Q] When a towel is bleached, loses 20% of its length and 10% of its breadth. Find the percentage decrease in area?
(a) 18&
(b) 28%
(c) 38%
(d) 48%

Solution

Answer   (b)
Explanation
---- 
Let original length and breadth = 100.
Then, original area = 100 × 100 = 10000

After losing 20% of length⇒New length = Original length×(100−20)100=100×80100=80After losing 10% of breadth⇒New breadth= Original breadth×(100−10)100=100×90100=90

New area = 80  × 90 = 7200



Decrease in area = Original Area - New Area = 10000 - 7200 = 2800

Percentage decrease in area = Decrease in AreaOriginal Area×100=280010000×100=28%

[Q] Find the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
(a) 841
(b) 414
(c) 541
(d) 814

Solution

Answer   (d)
Explanation
---- 

Hence, HCF of 1517 and 902 = 41



Hence, side length of largest square tile we can take = 41 cm

Area of each square tile = 41 × 41 cm2

Number of tiles required = 1517×90241×41=37×22=407×2=814

[Q] A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing such that poles of the fence are 5 metres apart. Find the number of poles.
(a) 56
(b) 45
(c) 36
(d) 65

Solution

Answer   (a)
Explanation
---- 

perimeter of the wire fencing =  = 2(90 + 50) = 280 metres
Two poles are 5 metres apart.

Hence number of poles required = ²⁸⁰⁄₅ = 56

Time and work Quantitative aptitude question

[Q] A and B working together can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B leaves and A alone completes the remaining work. The whole work was completed in how many days?
(a) 16 days
(b) 18 days
(c) 14 days
(d) 12 days

Solution

Answer   (d)
Explanation
----
Work done by A in 1 day = 1/15

Work done by B in 1 day = 1/10



Work done by A and B in 1 day = 1/15 + 1/10 = 1/6

Work done by A and B in 2 days = 2 × (1/6) = 1/3

Remaining work = 1 – 1/3 = 2/3



Time taken by A to complete the remaining work 2/3 = (2/3) / (1/15) = 10 days

Total time taken = 2 + 10 = 12 days

Time and work Quantitative aptitude question

[Q] A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B leaves and A alone and completes the remaining work. Then,the whole work was completed in how many days?
(a) 14 days
(b) 12 days
(c) 13 days
(d) 11 days

Solution

Answer   (b)
Explanation
----
Work done by A in 1 day = 1/15

Work done by B in 1 day = 1/10



Work done by A and B in 1 day = 1/15 + 1/10 = 1/6

Work done by A and B in 2 days = 2 × (1/6) = 1/3

Remaining work = 1 – 1/3 = 2/3



Time taken by A to complete the remaining work 2/3 = (2/3) / (1/15) = 10 days

Total time taken = 2 + 10 = 12 days

Time and work Quantitative aptitude question

[Q] X takes twice as much time as Y or thrice as much time as Z to finish a piece of work. If Working together, they can finish the work in 2 days. Then, working alone, how many days will Y take to complete the work?
(a) 5 days
(b) 6 days
(c) 4 days
(d) 7 days

Solution

Answer   (b)
Explanation
----
Let X takes x days to complete the work,

Then Y takes x/2 days and Z takes x/3 days to complete the work

Amount of work X does in 1 day = 1/x

Amount of work Y does in 1 day = 2/x

Amount of work Z does in 1 day = 3/x

Amount of work X,Y and Z do in 1 day = 1/x + 2/x + 3/x = 1/x (1 + 2 + 3) = 6/x

6/x = 2

=> x = 12

=> Y takes 12/2 days = 6 days to complete the work