[Q] X takes twice as much time as Y or thrice as much time as Z to finish a
piece of work. If Working together, they can finish the work in 2 days. Then, working alone, how many days will Y
take to complete the work?
(a) 5 days
(b) 6 days
(c) 4 days
(d) 7 days
(a) 5 days
(b) 6 days
(c) 4 days
(d) 7 days
Solution
Answer
(b)
Explanation
----
Let X takes x days to complete the work,
Then Y takes x/2 days and Z takes x/3 days to complete the work
Amount of work X does in 1 day = 1/x
Amount of work Y does in 1 day = 2/x
Amount of work Z does in 1 day = 3/x
Amount of work X,Y and Z do in 1 day = 1/x + 2/x + 3/x = 1/x (1 + 2 + 3) = 6/x
6/x = 2
=> x = 12
=> Y takes 12/2 days = 6 days to complete the work
Explanation
----
Let X takes x days to complete the work,
Then Y takes x/2 days and Z takes x/3 days to complete the work
Amount of work X does in 1 day = 1/x
Amount of work Y does in 1 day = 2/x
Amount of work Z does in 1 day = 3/x
Amount of work X,Y and Z do in 1 day = 1/x + 2/x + 3/x = 1/x (1 + 2 + 3) = 6/x
6/x = 2
=> x = 12
=> Y takes 12/2 days = 6 days to complete the work
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