[Q] 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish
the same work in 2 days. 15 men and 20 women can do the same work in - days.
(a) 5 days
(b) 2 days
(c) 4 days
(d) 6 days
(a) 5 days
(b) 2 days
(c) 4 days
(d) 6 days
Solution
Answer
(c)
Explanation
----
Let work done by 1 man in 1 day = m,
work done by 1 woman in 1 day = w
Work done by 6 men and 8 women in 1 day = 1/10
=> 6m + 8w = 1/10
=> 60m + 80w = 1 ------ (1)
Work done by 26 men and 48 women in 1 day = 1/2
=> 26m + 48w = ½
=> 52m + 96w = 1 ------ (2)
Solving equation 1 and equation 2. We get m = 1/100 and w = 1/200
Work done by 15 men and 20 women in 1 day
= 15/100 + 20/200 =1/4
=> Time taken by 15 men and 20 women in doing the work = 4 days
Explanation
----
Let work done by 1 man in 1 day = m,
work done by 1 woman in 1 day = w
Work done by 6 men and 8 women in 1 day = 1/10
=> 6m + 8w = 1/10
=> 60m + 80w = 1 ------ (1)
Work done by 26 men and 48 women in 1 day = 1/2
=> 26m + 48w = ½
=> 52m + 96w = 1 ------ (2)
Solving equation 1 and equation 2. We get m = 1/100 and w = 1/200
Work done by 15 men and 20 women in 1 day
= 15/100 + 20/200 =1/4
=> Time taken by 15 men and 20 women in doing the work = 4 days
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