[Q] The present ages of A,B and C are in proportions 4 : 7 : 9. Eight years ago, the sum of
their ages was 56. What are their present ages (in years)?
(a) 16,28 and 36
(b) 16,38 and 26
(c) 26,28 and 26
(d) 16,28 and 46
(a) 16,28 and 36
(b) 16,38 and 26
(c) 26,28 and 26
(d) 16,28 and 46
Solution
Answer
(a)
Explanation
----
Let's take the present age of A,B and C as 4x, 7x and 9x respectively
(4x - 8) + (7x – 8) + (9x – 8) = 56
=> 20x = 80
=> x = 4
Hence the present age of A, B and C are 4×4, 7×4 and 9×4 respectively
ie, 16,28 and 36 respectively.
Explanation
----
Let's take the present age of A,B and C as 4x, 7x and 9x respectively
(4x - 8) + (7x – 8) + (9x – 8) = 56
=> 20x = 80
=> x = 4
Hence the present age of A, B and C are 4×4, 7×4 and 9×4 respectively
ie, 16,28 and 36 respectively.
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