Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The ratio of the age of a man and his wife is 4:3. At the time of marriage the ratio was 5:3 and After 4 years this ratio will become 9:7. How many years ago were they married?
(a) 14
(b) 12
(c) 13
(d) 15

Solution

Answer   (a)
Explanation
----
Let the present age of the man and his wife be 4x and 3x respectively.

After 4 years this ratio will become 9 : 7
=> (4x + 4) : (3x + 4) = 9 : 7
=> 7(4x + 4) = 9(3x + 4)
=> 28x + 28 = 27x + 36
=> x = 8

Present age of the man = 4x = 4×8 = 32
Present age of his wife = 3x = 3×8 = 24

Assume that they got married before t years. Then
(32 – t) : (24 – t) = 5 : 3
3(32 – t) = 5(24 – t)
=> 96 – 3t = 120 – 5t
=> 2t = 24
=> t = 242 = 12

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] If 6 years are subtracted from the present age of Ajay and the remainder is divided by 18, then the present age of Rahul is obtained. If Rahul is 2 years younger to Denis whose age is 5 years, then what is Ajay 's present age?
(a) 60
(b) 50
(c) 70
(d) 80

Solution

Answer   (a)
Explanation
----
Present age of Denis = 5 years
Present age of Rahul = 5 - 2 = 3

Let the present age of Ajay = x
Then x−618 = present age of Rahul = 3
=> x - 6 = 3×18 = 54
=> x = 54 + 6= 60

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] Kamal was 4 times as old as his son 8 years ago. After 8 years, Kamal will be twice as old as his son. Find out the present age of Kamal.
(a) 54
(b) 30
(c) 44
(d) 40

Solution

Answer    (d)
Explanation
----
Let the age of the son before 8 years = x
Then age of Kamal before 8 years ago = 4x

After 8 years, Kamal will be twice as old as his son
=> 4x + 16 = 2(x + 16)
=> x = 8

Present age of Kamal = 4x + 8 = 4×8 + 8 = 40

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The present age of a father is 3 years more than three times the age of his son. Three years hence, father's age will be 10 years more than twice the age of the son. What is father's present age?
(a) 11
(b) 44
(c) 33
(d) 22

Solution

Answer    (c)
Explanation
----
Let the present age the son = x
Then present age of the father = 3x + 3

Given that ,three years hence, father's age will be 10 years more than twice the age of the son
=> (3x + 3 + 3) = 2(x + 3) +10
=> x = 10

Father's present age = 3x + 3 = 3×10 + 3 = 33

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person
(a) 50
(b) 30
(c) 20
(d) 40

Solution

Answer    (b)
Explanation
----
Let's take the present age of the elder person = x
and the present age of the younger person = x – 16

(x – 6) = 3 (x - 16 - 6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 602=30

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. What is the ratio of their present ages?
(a) 3 : 7
(b) 5 : 7
(c) 7 : 3
(d) 7 : 5

Solution

Answer    (c)
Explanation
----
Let the age of the son before 10 years = x and age of the father before 10 years = 3x

(3x + 20) = 2(x + 20)
=> x = 20

Age of the son at present = x + 10 = 20 + 10 = 30
Age of the father at present = 3x + 10 = 3×20 + 10 = 70

Required ratio = 70 : 30 = 7 : 3

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] Sobha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
(a) 4
(b) 2
(c) 8
(d) 6

Solution

Answer    (d)
Explanation
----
Let Sobha's age = x and her brother's age = x-4

Sobha's father's age = x + 38
Sobha's mother's age = (x - 4) + 36

=> Sobha's father's age - Sobha's mother's age
= (x + 38) – [(x - 4) + 36]
= x + 38 – x + 4 – 36
= 6

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] A is as much younger than B and he is older than C. If the sum of the ages of B and C is 50 years, what is definitely the difference between B and A's age?
(a) 3
(b) 2
(c) 4
(d) Data Inadequate

Solution

Answer    (d)
Explanation
----
Age of C < Age of A < Age of B

Given that sum of the ages of B and C is 50 years.
Let's take B's age = x and C's age = 50-x

Now we need to find out B's age – A's age. But we cannot find out this with the given data.

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. What is the present age of the mother?
(a) 50
(b) 60
(c) 30
(d) 40

Solution

Answer    (d)
Explanation
----
Let the present age of the person = x
Then present age of the mother = 5x2

Given that, after 8 years, the person will be one-half of the age of his mother.
=> (x + 8) = 12(5x2+8)
=> 2x + 16 = 5x2+8
=> x2 = 8
=> x = 16

Present age of the mother = 5x2=5×162=40

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The present ages of A,B and C are in proportions 4 : 7 : 9. Eight years ago, the sum of their ages was 56. What are their present ages (in years)?
(a) 16,28 and 36
(b) 16,38 and 26
(c) 26,28 and 26
(d) 16,28 and 46

Solution

Answer    (a)
Explanation
----
Let's take the present age of A,B and C as 4x, 7x and 9x respectively

(4x - 8) + (7x – 8) + (9x – 8) = 56
=> 20x = 80
=> x = 4

Hence the present age of A, B and C are 4×4, 7×4 and 9×4 respectively
ie, 16,28 and 36 respectively.

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age my father when my brother was born?
(a) 32
(b) 23
(c) 42
(d) 24

Solution

Answer    (a)
Explanation
----
Let my age = x

Then
My brother's age = x + 3
My mother's age = x + 26
My sister's age = (x + 3) + 4 = x + 7
My father's age = (x + 7) + 28 = x + 35

=> age my father when my brother was born = x + 35 – (x + 3) = 32

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] At present, the ratio between the ages of Shekhar and Shobha is 4 : 3. After 6 years, Shekhar's age will be 26 years. Find out the age of Shobha at present?
(a) 13
(b) 14
(c) 15
(d) 16

Solution

Answer    (c)
Explanation
----
After 6 years, Shekhar's age will be 26 years
=> Present age of Shekhar = 26 – 6 = 20

Let present age of Shobha = x

Then
20x=43
x = 20×34=15

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] Six years ago, the ratio of the ages of Vimal and Saroj was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Saroj's age at present?
(a) 14
(b) 26
(c) 16
(d) 24

Solution

Answer    (c)
Explanation
----
Given that , six years ago, the ratio of the ages of Vimal and Saroj = 6 : 5

Hence we can assume that
age of Vimal six years ago = 6x
age of Saroj six years ago = 5x

After 4 years, the ratio of their ages = 11 : 10
=> (6x+10) : (5x + 10) = 11 : 10
=> 10(6x + 10) = 11(5x + 10)
=> 5x = 10
=> x = 105 = 2

Saroj's present age = 5x + 6 = 5×2 +6 = 16

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] Kiarn is younger than Bineesh by 7 years and their ages are in the respective ratio of 7 : 9, how old is Kiran?
(a) 24.5
(b) 25.4
(c) 25.6
(d) 24.4

Solution

Answer    (a)
Explanation
----
Let the ages of Kiran and Bineesh are 7x and 9x respectively

7x = 9x - 7
=> x = 72 = 3.5

Kiran's age = 7x = 7 × 3.5 = 24.5

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The sum of the present ages of a son and his father is 60 years. Six years ago, father's age was five times the age of the son. After 6 years, what will be son's age?
(a) 30 years
(b) 20 years
(c) 40 years
(d) 10 years

Solution

Answer    (b)
Explanation
----
Let the present age of the son = x, then
Present age of the father = 60-x

Six years ago father's age was 5 times the age of the son
=> (60-x)-6 = 5(x-6)
=> 84 = 6x
=> x = 846 = 14

Son's age after 6 years = x + 6 = 14 + 6 = 20 years

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] Ayisha's age is 1/6th of her father's age. Ayisha 's father's age will be twice the age of Shankar's age after 10 years. If Shankar's eight birthdays was celebrated two years before, then what is Ayisha 's present age.
(a) 5 years
(b) 7 years
(c) 6 years
(d) 4 years

Solution

Answer    (a)
Explanation
----
Consider Ayisha's present age = x
Then her father's age = 6x

Given that Ayisha 's father's age will be twice the age of Shankar's age after 10 years
=> Shankar's age after 10 years = 12(6x + 10) = 3x + 5

Also given that Shankar's eight birthdays was celebrated two years before
=> Shankar's age after 10 years = 8 + 12 = 20
=> 3x + 5 = 20
=> x = 153 = 5

Therefore, Ayisha 's present age = 5 years

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] A father said to his son, "I was as old as you are at the present at the time of your birth". If the father's age is 38 years now, what was the son's age five years back?
(a) 18
(b) 14
(c) 16
(d) 12

Solution

Answer    (b)
Explanation
----
Let the son's present age be x years.

Then, (38 - x) = x
=> 2x = 38
=> x = 382 = 19

Son's age 5 years back = 19-5 = 14

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The average age of a class of 22 students is 21 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher?
(a) 24
(b) 54
(c) 34
(d) 44

Solution

Answer    (d)
Explanation
----

Total age of all students = 22×21

Total age of all students + age of the teacher = 23 × 22

Age of the teacher = 23×22 – 22×21 = 22(23-21) = 22×2 = 44

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q]A is two years older than B who is twice as old as C. The total of the ages of A, B and C is 27. How old is B? 
(a) 30
(b) 20
(c) 10
(d) 40

Solution

Answer    (c)
Explanation
----
Let the age of C = x. Then

Age of B = 2x
Age of A = 2 + 2x

The total age of A,B and C =27
=> (2+2x) + 2x + x = 27
=> 5x = 25
=> x = 255 = 5

B's age = 2x = 2×5 = 10

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The sum of ages of 5 children born at the intervals of 3 years each is 50 years. Find out the age of the youngest child?
(a) 6
(b) 4
(c) 8
(d) 10

Solution

Answer    (b)
Explanation
----
Let the age of the youngest child = x
Then the ages of 5 children can be written as x, (x+3), (x+6),(x+9) and (x+12)

x + (x+3) + (x+6) + (x+9) + (x+12) = 50
=> 5x + 30 = 50
=> 5x = 20
=> x = 205 = 4