Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?
(a) 10
(b) 2
(c) 8
(d) 6

Solution

Answer    (b)
Explanation
----
 Assume that Sunil's present age = x.
Then father's present age = 3x + x = 4x

After 8 years, father's age = 212 times of Sunils' age
=> (4x+8) = 212(x+8)
=> 4x + 8 = 52(x + 8)
=> 8x + 16 = 5x + 40
=> 3x = 40 - 16 = 24
=> x = 243 = 8

After further 8 years,
Sunil's age = x + 8 + 8 = 8 + 8 + 8 = 24
Father's age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48

Father's age/Sunil's age = 4824 = 2