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Showing posts with label Problems based on Age-level-2. Show all posts
Showing posts with label Problems based on Age-level-2. Show all posts

Thursday, 13 August 2015

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The ratio of the age of a man and his wife is 4:3. At the time of marriage the ratio was 5:3 and After 4 years this ratio will become 9:7. How many years ago were they married?
(a) 14
(b) 12
(c) 13
(d) 15
Solution
Answer   (a)
Explanation
----
Let the present age of the man and his wife be 4x and 3x respectively.

After 4 years this ratio will become 9 : 7
=> (4x + 4) : (3x + 4) = 9 : 7
=> 7(4x + 4) = 9(3x + 4)
=> 28x + 28 = 27x + 36
=> x = 8

Present age of the man = 4x = 4×8 = 32
Present age of his wife = 3x = 3×8 = 24

Assume that they got married before t years. Then
(32 – t) : (24 – t) = 5 : 3
3(32 – t) = 5(24 – t)
=> 96 – 3t = 120 – 5t
=> 2t = 24
=> t = 242 = 12

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] If 6 years are subtracted from the present age of Ajay and the remainder is divided by 18, then the present age of Rahul is obtained. If Rahul is 2 years younger to Denis whose age is 5 years, then what is Ajay 's present age?
(a) 60
(b) 50
(c) 70
(d) 80
Solution
Answer   (a)
Explanation
----
Present age of Denis = 5 years
Present age of Rahul = 5 - 2 = 3

Let the present age of Ajay = x
Then x618 = present age of Rahul = 3
=> x - 6 = 3×18 = 54
=> x = 54 + 6= 60

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The ages of two persons differ by 16 years. 6 years ago, the elder one was 3 times as old as the younger one. What are their present ages of the elder person
(a) 50
(b) 30
(c) 20
(d) 40
Solution
Answer    (b)
Explanation
----
Let's take the present age of the elder person = x
and the present age of the younger person = x – 16

(x – 6) = 3 (x - 16 - 6)
=> x – 6 = 3x – 66
=> 2x = 60
=> x = 602=30

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] The age of father 10 years ago was thrice the age of his son. Ten years hence, father's age will be twice that of his son. What is the ratio of their present ages?
(a) 3 : 7
(b) 5 : 7
(c) 7 : 3
(d) 7 : 5
Solution
Answer    (c)
Explanation
----
Let the age of the son before 10 years = x and age of the father before 10 years = 3x

(3x + 20) = 2(x + 20)
=> x = 20

Age of the son at present = x + 10 = 20 + 10 = 30
Age of the father at present = 3x + 10 = 3×20 + 10 = 70

Required ratio = 70 : 30 = 7 : 3

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] Sobha's father was 38 years of age when she was born while her mother was 36 years old when her brother four years younger to her was born. What is the difference between the ages of her parents?
(a) 4
(b) 2
(c) 8
(d) 6
Solution
Answer    (d)
Explanation
----
Let Sobha's age = x and her brother's age = x-4

Sobha's father's age = x + 38
Sobha's mother's age = (x - 4) + 36

=> Sobha's father's age - Sobha's mother's age
= (x + 38) – [(x - 4) + 36]
= x + 38 – x + 4 – 36
= 6

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] A is as much younger than B and he is older than C. If the sum of the ages of B and C is 50 years, what is definitely the difference between B and A's age?
(a) 3
(b) 2
(c) 4
(d) Data Inadequate
Solution
Answer    (d)
Explanation
----
Age of C < Age of A < Age of B

Given that sum of the ages of B and C is 50 years.
Let's take B's age = x and C's age = 50-x

Now we need to find out B's age – A's age. But we cannot find out this with the given data.

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] A person's present age is two-fifth of the age of his mother. After 8 years, he will be one-half of the age of his mother. What is the present age of the mother?
(a) 50
(b) 60
(c) 30
(d) 40
Solution
Answer    (d)
Explanation
----
Let the present age of the person = x
Then present age of the mother = 5x2

Given that, after 8 years, the person will be one-half of the age of his mother.
=> (x + 8) = 12(5x2+8)
=> 2x + 16 = 5x2+8
=> x2 = 8
=> x = 16

Present age of the mother = 5x2=5×162=40

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] My brother is 3 years elder to me. My father was 28 years of age when my sister was born while my mother was 26 years of age when I was born. If my sister was 4 years of age when my brother was born, then what was the age my father when my brother was born?
(a) 32
(b) 23
(c) 42
(d) 24
Solution
Answer    (a)
Explanation
----
Let my age = x

Then
My brother's age = x + 3
My mother's age = x + 26
My sister's age = (x + 3) + 4 = x + 7
My father's age = (x + 7) + 28 = x + 35

=> age my father when my brother was born = x + 35 – (x + 3) = 32

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] Ayisha's age is 1/6th of her father's age. Ayisha 's father's age will be twice the age of Shankar's age after 10 years. If Shankar's eight birthdays was celebrated two years before, then what is Ayisha 's present age.
(a) 5 years
(b) 7 years
(c) 6 years
(d) 4 years
Solution
Answer    (a)
Explanation
----
Consider Ayisha's present age = x
Then her father's age = 6x

Given that Ayisha 's father's age will be twice the age of Shankar's age after 10 years
=> Shankar's age after 10 years = 12(6x + 10) = 3x + 5

Also given that Shankar's eight birthdays was celebrated two years before
=> Shankar's age after 10 years = 8 + 12 = 20
=> 3x + 5 = 20
=> x = 153 = 5

Therefore, Ayisha 's present age = 5 years

Problems based on Age for IBPS, SBI, RBI, UPSC, State-psc Railways,SSC Clerk. PO

[Q] Father is aged three times more than his son Sunil. After 8 years, he would be two and a half times of Sunil's age. After further 8 years, how many times would he be of Sunil's age?
(a) 10
(b) 2
(c) 8
(d) 6
Solution
Answer    (b)
Explanation
----
 Assume that Sunil's present age = x.
Then father's present age = 3x + x = 4x

After 8 years, father's age = 212 times of Sunils' age
=> (4x+8) = 212(x+8)
=> 4x + 8 = 52(x + 8)
=> 8x + 16 = 5x + 40
=> 3x = 40 - 16 = 24
=> x = 243 = 8

After further 8 years,
Sunil's age = x + 8 + 8 = 8 + 8 + 8 = 24
Father's age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48

Father's age/Sunil's age = 4824 = 2

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