[Q] The ratio of the age of a man and his wife is 4:3. At the time of marriage the ratio was
5:3 and After 4 years this ratio will become 9:7. How many years ago were they married?
(a) 14
(b) 12
(c) 13
(d) 15
(a) 14
(b) 12
(c) 13
(d) 15
Solution
Answer
(a)
Explanation
----
Let the present age of the man and his wife be 4x and 3x respectively.
After 4 years this ratio will become 9 : 7
=> (4x + 4) : (3x + 4) = 9 : 7
=> 7(4x + 4) = 9(3x + 4)
=> 28x + 28 = 27x + 36
=> x = 8
Present age of the man = 4x = 4×8 = 32
Present age of his wife = 3x = 3×8 = 24
Assume that they got married before t years. Then
(32 – t) : (24 – t) = 5 : 3
3(32 – t) = 5(24 – t)
=> 96 – 3t = 120 – 5t
=> 2t = 24
=> t =242 = 12
Explanation
----
Let the present age of the man and his wife be 4x and 3x respectively.
After 4 years this ratio will become 9 : 7
=> (4x + 4) : (3x + 4) = 9 : 7
=> 7(4x + 4) = 9(3x + 4)
=> 28x + 28 = 27x + 36
=> x = 8
Present age of the man = 4x = 4×8 = 32
Present age of his wife = 3x = 3×8 = 24
Assume that they got married before t years. Then
(32 – t) : (24 – t) = 5 : 3
3(32 – t) = 5(24 – t)
=> 96 – 3t = 120 – 5t
=> 2t = 24
=> t =
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