[Q] The age of father 10 years ago was thrice the age of his son. Ten years hence, father's
age will be twice that of his son. What is the ratio of their present ages?
(a) 3 : 7
(b) 5 : 7
(c) 7 : 3
(d) 7 : 5
(a) 3 : 7
(b) 5 : 7
(c) 7 : 3
(d) 7 : 5
Solution
Answer
(c)
Explanation
----
Let the age of the son before 10 years = x and age of the father before 10 years = 3x
(3x + 20) = 2(x + 20)
=> x = 20
Age of the son at present = x + 10 = 20 + 10 = 30
Age of the father at present = 3x + 10 = 3×20 + 10 = 70
Required ratio = 70 : 30 = 7 : 3
Explanation
----
Let the age of the son before 10 years = x and age of the father before 10 years = 3x
(3x + 20) = 2(x + 20)
=> x = 20
Age of the son at present = x + 10 = 20 + 10 = 30
Age of the father at present = 3x + 10 = 3×20 + 10 = 70
Required ratio = 70 : 30 = 7 : 3
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