Janakalyan Sahakari Bank job recruitmemt notification

.

RRB Recruitment 2015 – Apply Online for 651 Jr, Accounts Clerk cum Typist & Other Posts: Government of India, Ministry of Railways, Railway Recruitment Board (RRB) has issued notification for the special recruitment of 651 Jr, Accounts Clerk cum Typist, Trains Clerk, Commercial Clerk & Ticket Examiner vacancies for PWD candidates. Eligible candidates can apply online from 22-08-2015 to 21-09-2015 up to 23.59 Hrs. Other details like age limit, qualification, selection process, application fee, how to apply are given below…

RRB Vacancy Details:
Total No.of Posts: 651
Name of the Posts:
1. Jr. Clerk cum Typist: 301 Posts
A. Ahmedabad: 28 Posts
B. Ajmer: 08 Posts
C. Allahabad: 20 Posts
D. Bangalore: 31 Posts
E. Bhopal: 10 Posts
F. Bhubaneswar: 04 Posts
G. Bilaspur: 24 Posts
H. Chandigarh: 08 Posts
I. Chennai: 11 Posts
J. Gorakhpur: 01 Post
K. Guwahati: 10 Posts
L. Kolkata: 62 Posts
M. Mumbai: 62 Posts
N. Muzaffarpur: 01 Post
O. Patna: 09 Posts
P. Ranchi: 11 Posts
Q. Secunderabad: 01 Post
2. Accounts Clerk cum Typist: 55 Posts
A. Ahmedabad: 03 Posts
B. Allahabad: 01 Post
C. Bangalore: 14 Posts
D. Bhopal: 01 Post
E. Chennai: 01 Post
F. Guwahati: 01 Post
G. Mumbai: 33 Posts
H. Muzaffarpur: 01 Post
3. Trains Clerk: 29 Posts
A. Ahmedabad: 06 Posts
B. Allahabad: 02 Posts
C. Bhopal: 07 Posts
D. Kolkata: 04 Posts
E. Malda: 01 Post
F. Mumbai: 07 Posts
G. Muzaffarpur: 02 Posts
4. Commercial Clerk: 86 Posts
A. Ahmedabad: 17 Posts
B. Ajmer: 07 Posts
C. Allahabad: 05 Posts
D. Bhopal: 11 Posts
E. Bhubaneswar: 01 Post
F. Bilaspur: 04 Posts
G. Chennai: 04 Posts
H. Guwahati: 01 Post
I. Kolkata: 23 Posts
J. Mumbai: 09 Posts
K. Siliguri: 02 Posts
L. Thiruvanantapuram: 02 Posts
5. Ticket Examiner: 180 Posts
A. Ahmedabad: 40 Posts
B. Ajmer: 15 Posts
C. Allahabad: 16 Posts
D. Bangalore: 23 Posts
E. Bhopal: 16 Posts
F. Bhubaneswar: 02 Posts
G. Chandigarh: 05 Posts
H. Chennai: 10 Posts
I. Guwahati: 04 Posts
J. Jammu & Srinagar: 01 Post
K. Kolkata: 19 Posts
L. Mumbai: 14 Posts
M. Ranchi: 01 Post
N. Secunderabad: 03 Posts
O. Siliguri: 04 Posts
P. Thiruvanantapuram: 07 Posts

Age Limit: Candidates age should be 18-29 years as on 01-01-2016. Age relaxations are applicable as per rules.

Educational Qualification: Candidates should possess 12th (+2 stage or its equivalent examination from recognized Board/ University/ Institute and typing speed of 30 wpm in English or 25 wpm in Hindi.

Selection Process: Selection will be made on the basis of written/ online examination, skill test, document verification & medical fitness.

Examination Fee: Candidates should have to pay Rs.100/- (for Editing/ Modification of Application fee) through online by using internet banking or debit/credit cards in any other banks except SBI or through Challan in any branch of SBI or computerized Post Office Pay-In-Slip.

How to Apply: Eligible candidates can apply online through the concerned RRB website (www.rrbahmedabad.gov.in) from 22-08-2015 to 21-09-2015 up to 23.59 Hrs.

Click for more details regarding this Job Notification

Instructions to Apply Online:
1. Log on through the website of RRB (www.rrbahmedabad.gov.in) to which the candidate wants to apply.
2. Click on the “Online Application” link.
3. Click on the “New Registration” link.
4. Fill the basic details carefully & select the post applied for.
5. Fill the other details carefully and submit the application form.
6. Registration Number & Password will be displayed on the screen.
7. Login using the Registration Number and Password.
8. Fill other relevant personal details.
9. Now pay the fee through Net Banking/ debit/ credit card/ challan form/ Pay-in-slip in any bank rather than SBI.
10. Download the blank “Template” by clicking on the link “Download Template”.
11. Affix your colour photograph (of size 3.5 cm x 3.5 cm), clear left hand thumb impression,
Signature and also copy the declaration
12. Scan the duly filled “Template” in prescribed format.
13. Submit the application form and take the printout copies of application form for future use.
14. Even after final submission if a candidate wishes to make any modifications.
15. Candidates have to pay Rs.100/- for modification for all category candidates.

Important Dates:
Starting Date to Apply Online: 22-08-2015.
Last Date to Apply Online: 21-09-2015 up to 23.59 Hrs.
Last Date for Reprint Application: 05-10-2015 .
Date of Online Fee Payment: 22-08-2015 to 20-09-2015.
Date of Offline Fee Payment (through SBI/ Post Office Challan): 22-08-2015 to 18-09-2015.
Date of Written/ Online Examination: Between 24-10-2015 to 04-11-2015.

For more details like pay scale, qualification & other information click on the link given below…

RRB – Jr, Accounts Clerk cum Typist, Clerk & Ticket Examiner Recruitment 2015	More Information
RRB – Jr, Accounts Clerk cum Typist, Clerk & Ticket Examiner Recruitment Advt	Get Details
Online Application	Click here
RRB – How to Apply	Get Details
RRB – Guidelines	Get Details
RRB – FAQ	Get Details

Other posts you might be interested in:

1. Collector Office Amravati Recruitment 2015 – Apply Online for Clerk Typist & Talathi Posts
2. Collector Office Satara Recruitment 2015 – Apply Online for 62 Clerk Typist & Talathi Posts
3. Ratnagiri Collector Office Recruitment 2015 – Apply Online for 43 Clerk Typist & Talathi Posts
4. Collector Office Dhule Recruitment 2015 – Apply Online for Clerk Typist Posts
5. Collector Office Wardha Recruitment 2015 – Apply Online for Clerk Typist

Questions on Area - Quantitative Aptitude

[Q] Find the percentage of error in the calculated area of the square if an error 2% in excess is made while measuring the side of  it. 
(a) 3.04%
(b) 2.04%
(c) 4.04%
(d) 5.04%

Solution

Answer   (c)
Explanation
---- 

Error = 2%
Let the correct value of the side of the square = 100

Then, the measured value = 100×(100+2)100=102 (∵ error 2% in excess)

Correct area of the square = 100 × 100 = 10000

Calculated area of the square = 102 × 102 = 10404

Error = 10404 - 10000 = 404

Percentage Error = ErrorActual Value×100=40410000×100=4.04%

[Q] A rectangular park 60 m long and 40 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. The area of the lawn is 2109 sq. m. Find the width of the road?
(a) 4
(b) 5
(c) 3
(d) 6

Solution

Answer   (c)
Explanation
---- 
Area of the park = (60 x 40) m² = 2400 m².
Area of the lawn = 2109 m².
Area of the crossroads = (2400 - 2109) m² = 291 m².
Let the width of the road be x metres. Then,
60x + 40x - x² = 291
x² - 100x + 291 = 0
(x - 97)(x - 3) = 0
x = 3.

[Q] When a towel is bleached, loses 20% of its length and 10% of its breadth. Find the percentage decrease in area?
(a) 18&
(b) 28%
(c) 38%
(d) 48%

Solution

Answer   (b)
Explanation
---- 
Let original length and breadth = 100.
Then, original area = 100 × 100 = 10000

After losing 20% of length⇒New length = Original length×(100−20)100=100×80100=80After losing 10% of breadth⇒New breadth= Original breadth×(100−10)100=100×90100=90

New area = 80  × 90 = 7200



Decrease in area = Original Area - New Area = 10000 - 7200 = 2800

Percentage decrease in area = Decrease in AreaOriginal Area×100=280010000×100=28%

[Q] Find the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?
(a) 841
(b) 414
(c) 541
(d) 814

Solution

Answer   (d)
Explanation
---- 

Hence, HCF of 1517 and 902 = 41



Hence, side length of largest square tile we can take = 41 cm

Area of each square tile = 41 × 41 cm2

Number of tiles required = 1517×90241×41=37×22=407×2=814

[Q] A rectangular plot measuring 90 metres by 50 metres is to be enclosed by wire fencing such that poles of the fence are 5 metres apart. Find the number of poles.
(a) 56
(b) 45
(c) 36
(d) 65

Solution

Answer   (a)
Explanation
---- 

perimeter of the wire fencing =  = 2(90 + 50) = 280 metres
Two poles are 5 metres apart.

Hence number of poles required = ²⁸⁰⁄₅ = 56

Time and work Quantitative aptitude question

[Q] A and B working together can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B leaves and A alone completes the remaining work. The whole work was completed in how many days?
(a) 16 days
(b) 18 days
(c) 14 days
(d) 12 days

Solution

Answer   (d)
Explanation
----
Work done by A in 1 day = 1/15

Work done by B in 1 day = 1/10



Work done by A and B in 1 day = 1/15 + 1/10 = 1/6

Work done by A and B in 2 days = 2 × (1/6) = 1/3

Remaining work = 1 – 1/3 = 2/3



Time taken by A to complete the remaining work 2/3 = (2/3) / (1/15) = 10 days

Total time taken = 2 + 10 = 12 days

Time and work Quantitative aptitude question

[Q] A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 2 days B leaves and A alone and completes the remaining work. Then,the whole work was completed in how many days?
(a) 14 days
(b) 12 days
(c) 13 days
(d) 11 days

Solution

Answer   (b)
Explanation
----
Work done by A in 1 day = 1/15

Work done by B in 1 day = 1/10



Work done by A and B in 1 day = 1/15 + 1/10 = 1/6

Work done by A and B in 2 days = 2 × (1/6) = 1/3

Remaining work = 1 – 1/3 = 2/3



Time taken by A to complete the remaining work 2/3 = (2/3) / (1/15) = 10 days

Total time taken = 2 + 10 = 12 days

Time and work Quantitative aptitude question

[Q] X takes twice as much time as Y or thrice as much time as Z to finish a piece of work. If Working together, they can finish the work in 2 days. Then, working alone, how many days will Y take to complete the work?
(a) 5 days
(b) 6 days
(c) 4 days
(d) 7 days

Solution

Answer   (b)
Explanation
----
Let X takes x days to complete the work,

Then Y takes x/2 days and Z takes x/3 days to complete the work

Amount of work X does in 1 day = 1/x

Amount of work Y does in 1 day = 2/x

Amount of work Z does in 1 day = 3/x

Amount of work X,Y and Z do in 1 day = 1/x + 2/x + 3/x = 1/x (1 + 2 + 3) = 6/x

6/x = 2

=> x = 12

=> Y takes 12/2 days = 6 days to complete the work

Time and work Quantitative aptitude question

[Q] A and B are working on an assignment. A takes 6 hours to type 32 pages on a computer, while B takes 5 hours to type 40 pages. How much time will A and B take, working together on two different computers to type an assignment of 110 pages?
(a) 10 hour 15 minutes
(b) 7 hour 15 minutes
(c) 8 hour 15 minutes
(d) 9 hour 15 minutes

Solution

Answer   (c)
Explanation
----
Pages typed by A in 1 hour = 32/6 = 16/3

Pages typed by B in 1 hour = 40/5 = 8

Pages typed by A and B in 1 hour = 16/3 + 8 = 40/3

Time taken to type 110 pages when A and B work together = 110 × 3 /40 = 33/4

= 8 ¼ hours = 8 hour 15 minutes

Time and work Quantitative aptitude question

[Q] A can do a piece of work in 20 days. B is 25% more efficient than A. The number of days taken by B to do the same piece of work is?

(a) 14 days
(b) 15 days
(c) 16 days
(d) 13 days

Solution

Answer   (c)
Explanation
----
Work done by A in 1 day = 1/20

Work done by B in 1 day = (1/20) × (125/100) = 5/80 = 1/16

=> B can complete the work in 16 days

Time and work Quantitative aptitude question

[Q] If A, B and C can complete a piece of work in 24, 6 and 12 days respectively. Then, working together, they will complete the same work in how many days?
(a) 3 ³⁄₇
(b) 2 ³⁄₇
(c) 5 ³⁄₇
(d) 4 ³⁄₇

Solution

Answer   (a)
Explanation
----
Work done by A in 1 day = 1/24

Work done by B in 1 day = 1/6

Work done by C in 1 day = 1/12

Work done by A,B and C in 1 day = 1/24 + 1/6 + 1/12 = 7/24

=> Working together, they will complete the work in 24/7 days = 3 ³⁄₇ days

Time and work Quantitative aptitude question

[Q] If A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?
(a) 23 days
(b) 13 days
(c) 33 days
(d) 43 days

Solution

Answer   (b)
Explanation
----
Work done by A in 1 day = 1/23

Let work done by B in 1 day = b

b × (130/100) = 1/23

=> b = 100/(23×130) = 10/(23×13)

Work done by A and B in 1 day = 1/23 + 10/(23×13) = 23/(23×13)= 1/13

=> A and B together can do the work in 13 days

Time and work Quantitative aptitude question

[Q] A can finish a work in 18 days and B can do the same work in 15 days. B worked for 10 days and left the job. In how many days, A alone can finish the remaining work?
(a) 4
(b) 2
(c) 5
(d) 6

Solution

Answer   (d)
Explanation
----
Work done by A in 1 day = 1/18

Work done by B in 1 day = 1/15

Work done by B in 10 days = 10/15 = 2/3

Remaining work = 1 – 2/3 = 1/3

Number of days in which A can finish the remaining work = (1/3) / (1/18) = 6

Time and work Quantitative aptitude question

[Q] 4 men and 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?
(a) 60 days
(b) 40 days
(c) 50 days
(d) 30 days

Solution

Answer   (b)
Explanation
----

Work done by 4 men and 6 women in 1 day = 1/8

Work done by 3 men and 7 women in 1 day = 1/10

Let 1 man does m work in 1 day and 1 woman does w work in 1 day. The above equations can be written as

4m + 6w = 1/8 ---(1)

3m + 7w = 1/10 ---(2)

Solving equation (1) and (2) , we get m=11/400 and w=1/400

Amount of work 10 women can do in a day = 10 × (1/400) = 1/40

Ie, 10 women can complete the work in 40 days

Time and work Quantitative aptitude question

[Q] A machine P can print one lakh books in 8 hours, machine Q can print the same number of books in 10 hours while machine R can print them in 12 hours. All the machines are started at 9 A.M. while machine P is closed at 11 A.M. and the remaining two machines complete work. Approximately at what time will the work (to print one lakh books) be finished ?
(a) 4 pm
(b) 3 pm
(c) 2 pm
(d) 1 pm

Solution

Answer   (d)
Explanation
----
Work done by P in 1 hour = 1/8

Work done by Q in 1 hour = 1/10

Work done by R in 1 hour = 1/12

Work done by P,Q and R in 1 hour = 1/8 + 1/10 + 1/12 = 37/120

Work done by Q and R in 1 hour = 1/10 + 1/12 = 22/120 = 11/60



From 9 am to 11 am, all the machines were operating.

Ie, they all operated for 2 hours and work completed = 2 × (37/120) = 37/60



Pending work = 1- 37/60 = 23/60

Hours taken by Q an R to complete the pending work = (23/60) / (11/60) = 23/11

which is approximately equal to 2

Hence the work will be completed approximately 2 hours after 11 am ; ie around 1 pm

Time and work Quantitative aptitude question

[Q] 6 men and 8 women can complete a work in 10 days. 26 men and 48 women can finish the same work in 2 days. 15 men and 20 women can do the same work in - days.
(a) 5 days
(b) 2 days
(c) 4 days
(d) 6 days

Solution

Answer   (c)
Explanation
----
Let work done by 1 man in 1 day = m,
work done by 1 woman in 1 day = w

Work done by 6 men and 8 women in 1 day = 1/10

=> 6m + 8w = 1/10

=> 60m + 80w = 1 ------ (1)

Work done by 26 men and 48 women in 1 day = 1/2

=> 26m + 48w = ½

=> 52m + 96w = 1 ------  (2)

Solving equation 1 and equation 2. We get m = 1/100 and w = 1/200

Work done by 15 men and 20 women in 1 day

= 15/100 + 20/200 =1/4

=> Time taken by 15 men and 20 women in doing the work = 4 days

Time and work Quantitative aptitude question

[Q] A alone can do a piece of work in 6 days and B alone can do it in 8 days. A and B undertook to do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be paid to C?
(a) 400
(b) 200
(c) 300
(d) 100

Solution

Answer   (a)
Explanation
----
Amount of work A can do in 1 day = 1/6

Amount of work B can do in 1 day = 1/8

Amount of work A + B can do in 1 day = 1/6 + 1/8 = 7/24

Amount of work A + B + C can do = 1/3

Amount of work C can do in 1 day = 1/3 - 7/24 = 1/24

work A can do in 1 day: work B can do in 1 day: work C can do in 1 day

= 1/6 : 1/8 : 1/24 = 4 : 3 : 1

Amount to be paid to C = 3200 × (1/8) = 400

Time and work Quantitative aptitude question

[Q] P is thrice as good as workman as Q and therefore is able to finish a job in 60 days less than Q. Working together, they can do it in:
(a) 20 ½ days
(b) 22 ½ days
(c) 21 ½ days
(d) 23 ½ days

Solution

Answer   (b)
Explanation
----
If P completes a work in 1 day, Q completes the same work in 3 days

Hence, if the difference is 2 days, Q can complete the work in 3 days

=> if the difference is 60 days, Q can complete the work in 90 days

=> Amount of work Q can do in 1 day= 1/90

Amount of work P can do in 1 day = 3 × (1/90) = 1/30

Amount of work P and Q can together do in 1 day = 1/90 + 1/30 = 4/90 = 2/45

=> P and Q together can do the work in 45/2 days = 22 ½ days

Time and work Quantitative aptitude question

[Q] A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
(a) 45 days
(b) 15 days
(c) 30 days
(d) 25 days

Solution

Answer   (b)
Explanation
----
Amount of work A can do in 1 day = 1/20

Amount of work B can do in 1 day = 1/30

Amount of work C can do in 1 day = 1/60

A is working alone and every third day B and C is helping him

Work completed in every three days = 2 × (1/20) + (1/20 + 1/30 + 1/60) = 1/5

So work completed in 15 days = 5 × 1/5 = 1

Ie, the work will be done in 15 days

Time and work Quantitative aptitude question

[Q] A can lay railway track between two given stations in 16 days and B can do the same job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job in how much days?
(a) 9 (1/5) days
(b) 9 (3/5) days
(c) 9 (2/5) days
(d) 9 (4/5) days

Solution

Answer   (b)
Explanation
----

Amount of work A can do in 1 day = 1/16

Amount of work B can do in 1 day = 1/12

Amount of work A, B and C can together do in 1 day = 1/4

Amount of work C can do in 1 day = 1/4 - (1/16 + 1/12) = 3/16 – 1/12 = 5/48

=> Hence C can do the job on 48/5 days = 9 (3/5) days

Time and work Quantitative aptitude question

[Q] A can do a work in 15 days and B in 20 days. If they work on it together for 4 days, Find the fraction of the work that is left

(a) 15/8
(b) 8/15
(c) 17/8
(d) 8/17

Solution

Answer   (b)
Explanation
----
Amount of work A can do in 1 day = 1/15

Amount of work B can do in 1 day = 1/20

Amount of work A and B can do in 1 day = 1/15 + 1/20 = 7/60

Amount of work A and B can together do in 4 days = 4 × (7/60) = 7/15

Fraction of work left = 1 – 7/15= 8/15

Problems on Trains

[Q] If a train running at a speed of 72 km/hr crosses a post in 20 seconds. What is the length of the train?
(a) 200 m
(b) 300 m
(c) 400 m
(d) 500 m

Solution

Answer   (c)
Explanation
----
 Speed of the train, s = 72 km/hr = 72000/3600 m/s = 720/36 m/s

Time taken to cross the post, t = 20 seconds.

Distance Covered, (distance = speed × time) = st = (720/36)× 20 = 400 m .

[Q] A train runs at the speed of 90 kmph and crosses a 500 m long platform in 30 seconds. Find the length of the train?
(a) 150
(b) 250
(c) 350
(d) 450

Solution

Answer   (b)
Explanation
----
Speed of train = 90 kmph = 90 × (5 / 18) = 25 m/s

Distance covered = (500+ L), where L = length of the train.

Time taken to cross the post = 
[(Combined length of train + platform) / speed of train] = 30seconds

=> (500 + L) / 25 = 30

=> 500+ L = 750

=> L = 250m

[Q] A train having a length of 500 m passes a post in 50 seconds. Find the time taken by it to pass a platform having a length of 500 m?
(a) 200 seconds
(b) 100 seconds
(c) 300 seconds
(d) 400 seconds

Solution

Answer   (b)
Explanation
----
speed of the train (s) = (distance / time) 

= 500 / 50 = 10 m/s

Time taken to pass the post =
 [ (combined length of train + platform) / time ] =

= (500 + 500) / 10 = 100 seconds

[Q] A train 400 m long runs with a speed of 54 km/hr. What time will it take to pass a platform of 200 m long?
(a) 40 seconds
(b) 20 seconds
(c) 30 seconds
(d) 50 seconds

Solution

Answer   (a)
Explanation
----
Speed = 54 km/hr = 54 × (5 / 18) m/s = 15 m/s

Time taken to pass the platform =
 [(Combined length of the train + platform) / speed of train ]

= 400 + 200 = 600 meter

Time taken to cross the platform = 600 / 15 = 40 seconds 

[Q] Two trains, each of length 150 m are moving in opposite directions. They cross each other in  10 seconds. If one is moving twice as fast the other, then find the speed of the faster train.
(a) 20m/s
(b) 40m/s
(c) 10m/s
(d) 60m/s

Solution

Answer   (a)
Explanation
----
Total distance covered = (combined length of both trains) =
150 + 150 = 300 m

Time taken to cross each other = 10 seconds.

let the speed of slower train = s .

Then the speed of the faster train = 2s

So,Relative speed = s + 2s = 3s (both train moving in same direction)

3s = 300/10 m/s = 10 m/s

=> s = 10 m/s

=> Speed of the slower train = s = 10 m/s

and, Speed of the faster train = 2s = 2 × 10 m/s = 20m/s

[Q] An error 2% in excess is made while measuring the side of a square. What is the percentage of error in the calculated area of the square?
(a) 1
(b) 2
(c) 3
(d) 4

Solution

Answer   (a)
Explanation
----